Content: k3-50.doc.RAR (34.79 KB)
Uploaded: 26.04.2016

Positive responses: 0
Negative responses: 0

Sold: 2
Refunds: 0

Seller: Михаил_Перович

Ask a question

Loyalty discount! If the total amount of your purchases from the seller more than:

$1 the discount is 1%
$5 the discount is 2%
$10 the discount is 3%
$20 the discount is 5%
$50 the discount is 7%
$100 the discount is 10%
$200 the discount is 15%
Solution K3-50 (Figure K3.5 condition 0 SM Targ 1989)

The planar mechanism consists of rods 1, 2, 3, 4 and the slider B or E (Fig. K.0 - K3.7) or from the rods 1, 2, 3 and the sliders B and E (Fig. K3.8, K3. 9) connected to each other and to fixed supports O1, O2 by hinges; Point D is in the middle of the rod AB. The lengths of the rods are l1 = 0.4 m, l2 = 1.2 m, l3 = 1.4 m, l4 = 0.6 m, respectively. The position of the mechanism is determined by the angles α, β, γ, φ, θ. The values ​​of these angles and other specified values ​​are given in Table. KZa (for Figure 0-4) or in Table. KZB (for Figure 5-9); while in Table. КЗа ω1 and ω4 are constant quantities. Determine the values ​​indicated in the tables in the columns "Find". Arc arrows in the figures show how the corresponding angles should be plotted during the construction of the mechanism drawing: in the direction of or against the clockwise direction (for example, the angle γ in Figure 8 should be deposited from DB along the clockwise direction, and in Figure 9 - arrows, etc.). Draw a drawing from the rod, the direction of which is determined by the angle α; the slider with guides for greater visibility is represented as in the example of short-circuit (see Fig. The given angular velocity and angular acceleration are assumed to be directed counterclockwise, and the given velocity vB and the acceleration aB are from point B to b (in Fig. 5-9).


No feedback yet